Meet with us again, Fun For Brain !! We take from about S3. which could be responsible deserve to be called Professor. They said this about the most trivial. Consider the following:
How to find a number divisible:
a. divisible by 2
b. divisible by 3
c. divisible by 4
d. divisible by 5
e. divisible by 6
f. divisible by 9What these numbers ...???
Come on ... you're only given time only 3 minutes.
Here's his answer:
# Out divided by a
All positive integers divisible by 1. For example 1, 2, 3, 4, 5, etc..
# Out divided by 2
Positive integer is divisible by 2 must be an even number. So, the last digit must be a number 0, 2, 4, 6 or 8. For example, 5671238, 9012370, 8712376, etc..
# Out divided by 3
To determine whether these positive integers divisible by 3 or not, we need to add up all digits. If the number of digits divisible by 3, then the number is also divisible by 3. For example, 652 341 the number of digits is 6 + 5 + 2 + 3 + 4 + 1 = 21. Because 21 is divisible by 3, then 652 341 is also divisible by 3.
# Out divided by 4
To determine whether a positive integer divisible by 4 or not, we need the last two digits of the positive integers. If the last two digits of positive integers is divisible by 4 then also serve targeted positive integer divisible by 4. For example, the last two digits of positive integers is 96 787 696. 96 787 696 divisible by 4 it is also divisible by 4.
# Out divided by 5
Positive integer numbers last digit 0 or 5 can be ascertained divisible by 5. For example, 9123740 or 12347125.
# Out divided by 6
Numbers out in the sixth when the numbers are down at the 2 and 3.
# Out divided by 7
To find out the numbers for the 7, separate the numbers into groups ranging from the right. Each group consists of 3 digits. Start from the right with a +. Write the + and - alternately in front of each group. Sum. If the result is a multiple of 7, then the numbers can be in for 7. For example, 14294863492 is divisible by seven because -14 +294-863 +492 = -91 = 7 x (-13).
# Out divided by 8
Numbers down at the 8 when his last 3 numbers are multiples of 8. For example, 787,296 out of the 8 because 296 = 8 × 37.
# Out divisible by 9
Positive integer is divisible by 9 if the digits-digits added together and hold will be equal to 9. For example, if the digit-digit 1957023 sum will be 1 + 9 + 5 + 7 + 0 + 2 + 3 = 27, and if the digits of the 27 we sum up the number again will be equal to 2 + 7 = 9. So 1957023 is divisible by 9.
Hopefully everything is clear
By. Fun for Brain
# Out divided by a
All positive integers divisible by 1. For example 1, 2, 3, 4, 5, etc..
# Out divided by 2
Positive integer is divisible by 2 must be an even number. So, the last digit must be a number 0, 2, 4, 6 or 8. For example, 5671238, 9012370, 8712376, etc..
# Out divided by 3
To determine whether these positive integers divisible by 3 or not, we need to add up all digits. If the number of digits divisible by 3, then the number is also divisible by 3. For example, 652 341 the number of digits is 6 + 5 + 2 + 3 + 4 + 1 = 21. Because 21 is divisible by 3, then 652 341 is also divisible by 3.
# Out divided by 4
To determine whether a positive integer divisible by 4 or not, we need the last two digits of the positive integers. If the last two digits of positive integers is divisible by 4 then also serve targeted positive integer divisible by 4. For example, the last two digits of positive integers is 96 787 696. 96 787 696 divisible by 4 it is also divisible by 4.
# Out divided by 5
Positive integer numbers last digit 0 or 5 can be ascertained divisible by 5. For example, 9123740 or 12347125.
# Out divided by 6
Numbers out in the sixth when the numbers are down at the 2 and 3.
# Out divided by 7
To find out the numbers for the 7, separate the numbers into groups ranging from the right. Each group consists of 3 digits. Start from the right with a +. Write the + and - alternately in front of each group. Sum. If the result is a multiple of 7, then the numbers can be in for 7. For example, 14294863492 is divisible by seven because -14 +294-863 +492 = -91 = 7 x (-13).
# Out divided by 8
Numbers down at the 8 when his last 3 numbers are multiples of 8. For example, 787,296 out of the 8 because 296 = 8 × 37.
# Out divisible by 9
Positive integer is divisible by 9 if the digits-digits added together and hold will be equal to 9. For example, if the digit-digit 1957023 sum will be 1 + 9 + 5 + 7 + 0 + 2 + 3 = 27, and if the digits of the 27 we sum up the number again will be equal to 2 + 7 = 9. So 1957023 is divisible by 9.
Hopefully everything is clear
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